Train Name : 1025 (Express Train) | Train No : 1025
Classes : 2nd,3rd
Stops : 2
Duration : 2 Hrs 22 Mins
Days : Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
Train number 1025 is a train running between Veyangoda and Panaleeya. The two cities are located at a distance of 40.394 kms.
The train 1025 is named as 1025 (Express Train) . It leaves Veyangoda at 13:37. and reaches Panaleeya at 15:59.It takes 2 Hrs 22 Mins to reach from its source to the destination.
Some of the major stations that the train passes through on its way are . In a week, 1025 (Express Train) operates on Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday.
| Station name (code) | Arrival | Departure | Stop time | Classes | Days |
|---|---|---|---|---|---|
| Veyangoda | 13:37 | 13:38 | 1 minutes | 2nd,3rd | Sunday to Monday |
| Panaleeya | 2nd,3rd | Sunday to Monday |
Frequently Asked Questions
- What time 1025 (Express Train) depart from Veyangoda Railway Station ? 1025 (Express Train) departs from Veyangoda Railway Station at 13:37.
- How much time 1025 (Express Train) take to reach Panaleeya Station ? The arrival time of 1025 (Express Train) at Panaleeya Station is 15:59.
- Distance covered by 1025 (Express Train) ? 1025 (Express Train) covers 40.394 km to reach Panaleeya Station. 1025 (Express Train) passes through 2 stations.
- How to book a train ticket online in Sri Lanka? You can check various methods for booking here Click Here